(3x^4y^5/2x^-3y^4)^2

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Solution for (3x^4y^5/2x^-3y^4)^2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(x^-3*((3*x^4*y^5)/2)*y^4)^2 = 0

9/4*x^2*y^18 = 0 // : 9/4*y^18

x^2 = 0

x = 0

x in { 0} 

x belongs to the empty set

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